5x^2+55x+50x=0

Solution for 5x^2+55x+50x=0 equation:

5x^2+55x+50x=0

We add all the numbers together, and all the variables

5x^2+105x=0

a = 5; b = 105; c = 0;
Δ = b2-4ac
Δ = 1052-4·5·0
Δ = 11025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11025}=105$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(105)-105}{2*5}=\frac{-210}{10}
=-21
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(105)+105}{2*5}=\frac{0}{10}
=0
$